10x-12x^2=0

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Solution for 10x-12x^2=0 equation: 



10x-12x^2=0

a = -12; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-12)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-12}=\frac{-20}{-24}
=5/6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-12}=\frac{0}{-24}
=0
$

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